15 Aug, 2024
· Chemistry

The chemical formula of Lead (IV) chromate is

  1. Pb(CrO4)2\text{Pb(CrO}_4\text{)}_2
  2. Pb(CrO4)\text{Pb(CrO}_4\text{)}
  3. Pb2(CrO4)\text{Pb}_2\text{(CrO}_4\text{)}
  4. Pb2(CrO4)2\text{Pb}_2\text{(CrO}_4\text{)}_2
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Long Explanation

Explanation

The chemical formula of Lead (IV) chromate

The chemical symbol for lead is Pb\text{Pb}, and the oxidation state IV indicates that lead has a charge of +4+4. Chromate is represented by CrO4\text{CrO}_4, which has a charge of 2-2.

To find the chemical formula, we need to balance the total positive and negative charges. This can be achieved by combining one lead ion (IV) with two chromate ions, because:

Pb4++2(CrO42)Pb(CrO4)2\text{Pb}^{4+} + 2 (\text{CrO}_4^{2-}) \Rightarrow \text{Pb}(\text{CrO}_4)_2

Thus, the chemical formula for Lead (IV) chromate is Pb(CrO4)2\text{Pb}(\text{CrO}_4)_2.

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Johnathan Clark

Chemistry Content Writer at Math AI

Johnathan Clark, with a Master's in Chemistry from the University of São Paulo, is a young high school chemistry teacher and part-time contract writer. His engaging classroom experiments translate into compelling written content that makes chemistry exciting and practical.

chemistry
Concept

Oxidation States

Explanation

Oxidation states refer to the hypothetical charges that atoms would have if all bonds to atoms of different elements were fully ionic. This concept is essential in understanding various chemical reactions, especially redox reactions.

Rules for Determining Oxidation States

There are several guidelines for assigning oxidation states:

  1. The oxidation state of a free element (uncombined element) is always zero. For example, O2_2, H2_2, and N2_2 have oxidation states of 0.
  2. For a simple (monoatomic) ion, the oxidation state is equal to the net charge of the ion. For instance, Na+^+ has an oxidation state of +1 and Cl^- has an oxidation state of -1.
  3. Hydrogen generally has an oxidation state of +1 when bonded to non-metals and -1 when bonded to metals.
  4. Oxygen usually has an oxidation state of -2. Exceptions include peroxides (e.g., H2_2O2_2), where oxygen has an oxidation state of -1, and in compounds with fluorine, where it can be positive.
  5. In compounds, the sum of the oxidation states of all elements is equal to the net charge of the compound.

Example Calculation

For the molecule H2_2O (water):

  • Hydrogen's oxidation state: +1
  • Oxygen's oxidation state: -2

The sum should be zero since the molecule is neutral:

2(+1)+(2)=02(+1) + (-2) = 0

Redox Reactions

In redox reactions, oxidation states help identify which elements are oxidized and which are reduced:

  • Oxidation involves an increase in oxidation state.
  • Reduction involves a decrease in oxidation state.

For the reaction between magnesium and oxygen to form magnesium oxide:

2Mg+O22MgO2\text{Mg} + \text{O}_2 \rightarrow 2\text{MgO}

Magnesium changes from an oxidation state of 0 to +2, and oxygen changes from 0 to -2. Thus, magnesium is oxidized and oxygen is reduced.

Understanding oxidation states is key to grasping the principles of electron transfer in chemical reactions, making it a fundamental concept in both inorganic and organic chemistry.

Concept

Charge Balancing

Explanation of Charge Balancing in Chemistry

In chemistry, charge balancing refers to the process of ensuring that the total positive charge and the total negative charge in a chemical compound or solution are equal. This is fundamental for the stability and electrical neutrality of compounds.

Significance

Charge balancing is essential in:

  • Formulating correct chemical compounds: Ensuring the right stoichiometry in ionic compounds, complexes, and reactions.
  • Balancing redox reactions: Making sure that the transfer of electrons is balanced.
  • Electrochemistry: Understanding the movement of ions in cells and batteries.

Example: Ionic Compounds

Take the simple ionic compound, sodium chloride (NaCl). Sodium (Na) has a +1 charge and chloride (Cl) has a -1 charge. The charges balance each other out, resulting in a neutral compound.

Complex Compounds

For a compound like aluminum sulfate, Al2(SO4)3Al_2(SO_4)_3, the charge balance can be illustrated as follows:

  1. Identify charges:

    • Aluminum ion, Al3+Al^{3+}
    • Sulfate ion, SO42SO_4^{2-}
  2. Balance the charges:

    Total positive charge=2×(+3)=+6\text{Total positive charge} = 2 \times (+3) = +6 Total negative charge=3×(2)=6\text{Total negative charge} = 3 \times (-2) = -6

    Thus, the compound is electrically neutral because:

    +6+(6)=0+6 + (-6) = 0

Redox Reaction Balancing

In redox reactions, ensuring that the gain and loss of electrons are balanced is crucial. For instance, in the oxidation of iron by chlorine:

Fe2++Cl2Fe3++2ClFe^{2+} + Cl_2 \rightarrow Fe^{3+} + 2Cl^{-}

Here, iron is oxidized (losing one electron per Fe2+Fe3+Fe^{2+} \rightarrow Fe^{3+}) and chlorine is reduced (gaining two electrons per Cl22ClCl_2 \rightarrow 2Cl^{-}). Balancing these requires:

Fe: (Fe2+Fe3++e)\text{Fe: } (Fe^{2+} \rightarrow Fe^{3+} + e^{-}) Cl: (Cl2+2e2Cl)\text{Cl: } (Cl_2 + 2e^{-} \rightarrow 2Cl^{-})

Summary

Charge balancing ensures that the sum of all positive charges equals the sum of all negative charges in a compound, thereby maintaining electrical neutrality. This is crucial for correct chemical formulations and reaction equations.